F(-2)=2x^2-3x

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Solution for F(-2)=2x^2-3x equation: 



(-2)=2F^2-3F

We move all terms to the left:

(-2)-(2F^2-3F)=0

We add all the numbers together, and all the variables

-(2F^2-3F)-2=0

We get rid of parentheses

-2F^2+3F-2=0

a = -2; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-2)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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